2x^2-15x+36=20

Solution for 2x^2-15x+36=20 equation:

2x^2-15x+36=20

We move all terms to the left:

2x^2-15x+36-(20)=0

We add all the numbers together, and all the variables

2x^2-15x+16=0

a = 2; b = -15; c = +16;
Δ = b2-4ac
Δ = -152-4·2·16
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{97}}{2*2}=\frac{15-\sqrt{97}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{97}}{2*2}=\frac{15+\sqrt{97}}{4}
$